This documentation is automatically generated by online-judge-tools/verification-helper
#include "src/datastructure/CumulativeSum2D.hpp"2 次元累積和を用いてオフライン矩形和クエリを処理する.
#pragma once
#include <cassert>
#include <vector>
template <typename T> struct CumulativeSum2D {
CumulativeSum2D(const std::vector<std::vector<T>>& v) {
n = v.size(), m = v[0].size();
dat.assign(n + 1, std::vector<T>(m + 1, T(0)));
for (int i = 0; i < n; i++) {
for (int j = 0; j < m; j++) {
dat[i + 1][j + 1] = v[i][j];
dat[i + 1][j + 1] += dat[i + 1][j] + dat[i][j + 1] - dat[i][j];
}
}
}
T query(int xl, int xr, int yl, int yr) const { // [xl, xr) * [yl, yr)
assert(0 <= xl && xl <= xr && xr <= n);
assert(0 <= yl && yl <= yr && yr <= m);
return dat[xr][yr] - dat[xl][yr] - dat[xr][yl] + dat[xl][yl];
}
private:
int n, m;
std::vector<std::vector<T>> dat;
};#line 2 "src/datastructure/CumulativeSum2D.hpp"
#include <cassert>
#include <vector>
template <typename T> struct CumulativeSum2D {
CumulativeSum2D(const std::vector<std::vector<T>>& v) {
n = v.size(), m = v[0].size();
dat.assign(n + 1, std::vector<T>(m + 1, T(0)));
for (int i = 0; i < n; i++) {
for (int j = 0; j < m; j++) {
dat[i + 1][j + 1] = v[i][j];
dat[i + 1][j + 1] += dat[i + 1][j] + dat[i][j + 1] - dat[i][j];
}
}
}
T query(int xl, int xr, int yl, int yr) const { // [xl, xr) * [yl, yr)
assert(0 <= xl && xl <= xr && xr <= n);
assert(0 <= yl && yl <= yr && yr <= m);
return dat[xr][yr] - dat[xl][yr] - dat[xr][yl] + dat[xl][yl];
}
private:
int n, m;
std::vector<std::vector<T>> dat;
};